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Herman Cain has another soundbite bomb-dropper for us: He can bring African American voters to the Republican Party in 2012. The Washington Post reports that the self-described “Chocolate Walnut” sent out a mailer to Iowa voters saying that he can grab a large share of the black vote, “something that has not been done since Dwight Eisenhower garnered 41 percent of the black vote in 1956,” the note said.

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The Post also reports Cain’s campaign as saying he’ll be the GOP nominee because:

“He’s a descendant of slaves who can garner a large share of the black vote, he didn’t inherit a dime, he has traveled the globe for years, and he’s a believer in Jesus Christ.”

Really? Given that Cain has already insulted many black voters by saying they have been “brainwashed” into supporting the Democratic Party, his predictions seem pretty far-fetched.

“If he’s talking about 41 percent of black voters in the Republican primary, he might be right,” Michael Dawson, an African American political science professor at the University of Chicago, said with a chuckle. But in a general election against President Obama, who got 95 percent of the black vote in 2008 and remains popular among African Americans, Dawson said Cain “would be lucky to get 10 percent” of the black vote.

Read the full story in The Washington Post


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